0=m^2+11m+10

Solution for 0=m^2+11m+10 equation:

0=m^2+11m+10

We move all terms to the left:

0-(m^2+11m+10)=0

We add all the numbers together, and all the variables

-(m^2+11m+10)=0

We get rid of parentheses

-m^2-11m-10=0

We add all the numbers together, and all the variables

-1m^2-11m-10=0

a = -1; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·(-1)·(-10)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*-1}=\frac{2}{-2}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*-1}=\frac{20}{-2}
=-10
$